56x^2-8x-48=0

Solution for 56x^2-8x-48=0 equation:

56x^2-8x-48=0

a = 56; b = -8; c = -48;
Δ = b2-4ac
Δ = -82-4·56·(-48)
Δ = 10816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10816}=104$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-104}{2*56}=\frac{-96}{112}
=-6/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+104}{2*56}=\frac{112}{112}
=1
$